I define a contact surface offset between two asymmetric rings. Why is the radial displacement result so much smaller than original offset defined?
March 17, 2023 at 9:00 amFAQParticipant
Displacement result is a function of the relative stiffness between the two rings. It will only match the user defined offset if the outer ring is negligibly soft compared to the inner ring. See link to video below for simple demonstration. https://youtu.be/IEKnTSFa6zg
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